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Author: prateek sachan
Forked from: Harsh Jha/Mid-Term Assignment
Project access type: Public
Description:
Solution for 3rd:-
Here To make 32:5 priority encoder from 4 given 8:3 priority encoders we must follow the following steps:-
Firstly we should take four 8:3 priority encoders and name them PE1, PE2, PE3, PE4 on the basis of the inputs given, Then we should connect all of them with 32 inputs 0-31 accordingly.
Then we should connect Ei of PE1, PE2, PE3 with E0 of PE2, PE3, PE4 respectively.
Now take 5 inputs [00-04] and then take three And gates with 4 inputs and connect all outputs [00-02] to Ands of | A1 of all PEs, A2 of all PEs, A3 of all PEs|
respectively.
Now connect GS of PE2 and PE4 with AND gate and then connect that gate's output with output [o3].
Now connect GS of PE3 and PE4 with And the gate and then connect that gate's output with output [04].
So now our 32 inputs PE is ready.
Solution for 4th:-
Here 'X' state of logic output is used to indicate an invalid logic level while the Z-state of logic output is used to Indicating the Floating values.
If a BUS is driven to 0 & 1 by two enabled tristate buffers, the output is X-state while when enable of a tristate buffer is 0, Then the output is Z state(floating).
X- state logic output might change with a change in temperature, time but the Z-state output doesn't change.
Hence this is the solution.
Created: May 13, 2021
Updated: Aug 26, 2023
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